Flypitch Lean 4

3 Compactness And Completion

The next step is to understand how consistency behaves under enlarging a theory. The formalized route is the classical one: first prove that any proof uses only finitely many assumptions, then use this finitary principle to build maximal and hence complete consistent extensions. This chapter corresponds to Flypitch/Compactness.lean and Flypitch/Completion.lean.

3.1 Compactness As A Finitary Principle

The later Henkin construction repeatedly adds new sentences to a theory. To show that these enlargements preserve consistency, it is enough to know that an inconsistency can already be witnessed inside some finite fragment. The repository proves exactly this statement in proof-theoretic form.

Theorem 8 Proof Compactness

If a formula \(\psi \) is derivable from a set \(T\) of formulas, then there exists a finite subset \(\Gamma \subseteq T\) such that \(\Gamma \vdash \psi \).

Proof

The proof is by induction on a derivation of \(\psi \). Each inference rule uses only finitely many assumptions, and finite supports are combined by taking finite unions. The only delicate point is universal introduction, where one must descend from a lifted theory back to a finite family of original assumptions.

This is the precise finiteness statement needed later: a contradiction cannot depend essentially on infinitely many hypotheses at once.

3.2 Compactness For Theories

The rest of the development is phrased in terms of theories of sentences rather than arbitrary sets of formulas, so the same result is repackaged at the theory level.

Theorem 9 Theory Compactness

If a sentence \(\psi \) is provable from a theory \(T\), then there is a finite subtheory \(\Gamma \subseteq T\) from which \(\psi \) is already provable.

This is the form used in later consistency arguments. Whenever a large theory is inconsistent, the obstruction already appears in a finite collection of its sentences.

3.3 Controlled Unions

Compactness immediately gives a useful principle for enlarging consistent theories.

Proposition 10 Consistency Of A Controlled Union

Let \(T_1\) be a consistent theory. Suppose that every sentence \(\psi \) in a second theory \(T_2\) can be added to \(T_1\) without forcing inconsistency in the relevant one-step sense. Then the union \(T_1 \cup T_2\) is consistent.

Proof

Assume the union were inconsistent. By Theorem 9, some finite fragment is already inconsistent. One then adds the finitely many sentences coming from \(T_2\) one at a time and uses the hypothesis at each step to rule out the appearance of a contradiction.

This proposition is the first general tool showing that a large extension can be handled by checking one sentence at a time. It will be reused in the Henkin chapter.

3.4 Chains Of Consistent Extensions

To pass from a consistent theory to a maximal one, one considers the partially ordered set of all consistent extensions ordered by inclusion. The key point is that any chain of such extensions has an upper bound, namely its union.

Lemma 11 Finite Fragments Lie In One Chain Element
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Let \(c\) be a nonempty chain of consistent extensions of a theory \(T\). Every finite subset of the union of the chain is already contained in a single member of the chain.

This is immediate from finite induction and total comparability inside the chain.

Proposition 12 Consistency Of The Union Of A Chain

The union of a chain of consistent extensions of \(T\) is again consistent.

Proof

If the union were inconsistent, compactness would produce a finite inconsistent subtheory. By Lemma 11, that finite fragment would already lie in one element of the chain, contradicting the consistency of that element.

3.5 Maximal Consistent Extensions

Once unions of chains are known to preserve consistency, Zorn’s lemma applies.

Theorem 13 Maximal Consistent Extension

Every consistent theory has a maximal consistent extension.

Maximality then yields the expected dichotomy for sentences.

Proposition 14 A Maximal Consistent Extension Is Complete

If \(T_{\max }\) is maximal among the consistent extensions of a theory \(T\), then \(T_{\max }\) is complete.

Proof

Let \(\psi \) be any sentence. If neither \(\psi \) nor \(\neg \psi \) lies in \(T_{\max }\), then one of the two one-sentence enlargements remains consistent. That contradicts maximality.

Corollary 15 Completion Of A Consistent Theory

Every consistent theory has a complete consistent extension.

3.6 Why This Matters Later

The role of this chapter is straightforward.

  • Compactness turns inconsistency questions into finite calculations.

  • Controlled unions show how to adjoin families of new sentences while tracking consistency.

  • Completion turns a merely consistent theory into one that decides every sentence.

These are exactly the abstract ingredients needed before witness constants can be adjoined systematically in the Henkin construction.

3.7 Formalization Note

The Lean development packages these ideas through the theorems proof_compactness, theory_proof_compactness, is_consistent_union, consis_limit, maximal_extension, and complete_maximal_extension_of_consis. The mathematical content, however, is the standard compactness-and-Zorn argument just described.